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The slingshot is a popular attraction at many amusement parks. During the ride, riders sit in a ball and are propelled vertically by a massive slingshot. A certain sling shot uses 25 springs, each with a constant of . If the springs are stretched
and the ball reaches a maximum height of
when no riders are in it, what is the total mass of the ball?
Explanation
We can use the expression for conservation of energy to solve this problem:
Given the problem statement, we know that the ball has no velocity at the initial and final states, so we can remove kinetic energy from the equation:
The initial potential energy is stored in the springs and the final potential energy is gravitational, so we can write:
We multiply by 25 because there are 25 springs.
Rearranging for mass, we get:
We know all of these values, allowing us to solve:
A car is at rest at the bottom of a
hill.
later, it is at the top of the hill going
. Find the net work done.
Explanation
Initially the car is at rest at the bottom of a hill, this velocity and height are zero.
Converting to
Plugging in values:
Consider the following system:

Two spherical masses, A and B, are attached to the end of a rigid rod with length l. The rod is attached to a fixed point, p, which is at the midpoint between the masses and is at a height, h, above the ground. The rod spins around the fixed point in a vertical circle that is traced in grey. is the angle at which the rod makes with the horizontal at any given time (
in the figure).
The rod is initially at rest in its horizontal position. How much work would it take to rotate the rod clockwise until it is vertical, at rest, and mass A is at the top?
Neglect air resistance and internal frictional forces. Ignore the mass of the rod itself.
None of these
Explanation
We can use the expression for conservation of energy:
Since the rod is both initially and finally at rest, we can removed both kinetic energies. Also, if we assume point p is at a height of 0, we can removed initial potential energy, leaving us with:
Plugging in the expression for potential energy and expanding for both masses:
Since the rod is vertical, we know that mass A is half a rod's length above our reference height, and mass B is half a rod's length below it. Thus we get:
Factoring to clean up our expression:
We know all of our variables, so time to plug and chug:
Consider the following system:

Two spherical masses, A and B, are attached to the end of a rigid rod with length l. The rod is attached to a fixed point, p, which is at the midpoint between the masses and is at a height, h, above the ground. The rod spins around the fixed point in a vertical circle that is traced in grey. is the angle at which the rod makes with the horizontal at any given time (
in the figure).
The rod is initially at rest in its horizontal position. How much work would it take to rotate the rod clockwise until it is vertical, at rest, and mass A is at the top?
Neglect air resistance and internal frictional forces. Ignore the mass of the rod itself.
None of these
Explanation
We can use the expression for conservation of energy:
Since the rod is both initially and finally at rest, we can removed both kinetic energies. Also, if we assume point p is at a height of 0, we can removed initial potential energy, leaving us with:
Plugging in the expression for potential energy and expanding for both masses:
Since the rod is vertical, we know that mass A is half a rod's length above our reference height, and mass B is half a rod's length below it. Thus we get:
Factoring to clean up our expression:
We know all of our variables, so time to plug and chug:
The work done by a centripetal force on an object moving in a circle at constant speed is .
zero
equal to the kinetic energy of the object
equal to the force exerted
equal to the force exerted multiplied by the displacement
Explanation
Recall that work can be defined as:
Here, is the magnitude of the force vector,
is the magnitude of the displacement vector, and
is the angle between the directions of the force and displacement vectors. In the case of circular motion, the force vector is normal to the circle since it points inward, and the displacement vector is tangent to the circle. This means that the angle between the force vector and displacement is
. Since
, work done by the centripetal force on an object moving in a circle is always
.
Nicola is attempting to create a single tiered mobile as shown. She has a wooden dowel (,
), and two distinct bird ornaments (
,
) which she wishes to attach on either end of the dowel.

If Nicola places ornament ,
to the left of the dowel's midpoint, and ornament
,
to the right of the dowel's midpoint, where should she attach the mobile string in order for it to balance?
Note: figure not drawn to scale.
from the left end of the dowel
from the right end of the dowel
from the right end of the dowel
from the left end of the dowel
Explanation
Let's use the midpoint as our point of reference. With that said, is
from the center, and
is
from the center. However, each of these are on different sides of the midpoint. When we set up our center of gravity equation, we must determine a (+) and (-) side in order to denote under which side our mobile string will fall. It may be helpful to look at the mobile as a number line, with the left being negative, and the right side positive, but you can really use which ever is more comfortable.
Our main equation is this:
Where is our weight in newtons and
is our distance in meters. Typically, we would want to convert everything to SI units, so let's go ahead and do that (ex:
)
Now let's plug in our numbers, remember about our negative/positive sides!
This should give us
Now, because this number is negative, we know it's to the left of our midpoint (if you chose to set up your -/+ sides opposite of how we did it, your answer will be positive). Regardless of the outcome, this measurement is meant to be taken from object A to the midpoint. Well, do any of our answers have either (+) or (-) ? No. But if we read them carefully, we can determine that the answer is
from the left of the dowel by using simple subtraction.
One side is

Think about it logically too (use your pencil). The heavier end of a pencil usually has a bulky eraser on it (just like the bulkier object on the left). Try holding the pencil at the tip's end, and then gradually try balancing it in the same manner as you move closer to the eraser.
ALSO NOTE: the question states the weight of the dowel as well. But look we didn't even need it. Sometimes the AP exam will give you some aspects in the question to distract you.
During time period , a rocket ship deep in space of mass
travels from
to
. During time period
, the rocket fires. During time period
, the rocket travels from
to
.
Time periods ,
, and
took
each.
Determine the work done during time period .
None of these
Explanation
Using
Determining initial kinetic energy:
Combining equations
Converting to
and plugging in values:
Determining final kinetic energy:
Combining equations
Converting to
and plugging in values:
Plugging in values:
Which of the following variables are involved in the calculation of work?
I. Force
II. Distance
III. Acceleration
I, II and III
I only
II only
I and II
Explanation
Work is defined as:
Where is work,
is force experienced by the object/person, and
is the distance the object/person moves as a result of the force. Recall that force is calculated as follows.
Where is mass and
is acceleration; therefore, work depends on the mass and acceleration (force), and distance.
A box slides
down a
inclined plane. If
, calculate the magnitude of the work done by friction on the box,
. Your answer should only have
significant figures.
Explanation
In general,
In order to calculate the work done by a force, we need to find the angle between the force and the displacement through which the object moves. Since the displacement is directed down the incline, then this means the friction force acts up the incline. This means . We must remember the frictional force is represented as
Where is the normal force and
is the coefficient of kinetic friction. On an inclined plane, we can show that
. Therefore, we can finally write
Plugging in everything, and noting the magnitude is the absolute value of a quantity, we can plug in for our answer:
Fido, a small dog that weighs , sees a bird in a tree and climbs straight up, at constant velocity, with an average power of
. If it takes Fido
to reach the branch upon which the bird is perched, how high is that branch?
Explanation
We can assume that the dog must carry his entire weight up the tree, and therefore a force is exerted. Using the equation
we can use the evidence provided by the problem to solve for distance.