Add and Subtract Fractions with Unlike Denominators: CCSS.Math.Content.5.NF.A.1

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5th Grade Math › Add and Subtract Fractions with Unlike Denominators: CCSS.Math.Content.5.NF.A.1

Questions 1 - 10

Solve:

$\frac{7}{8}-\frac{3}{16}$

$\frac{11}{16}$

$\frac{4}{16}$

$\frac{4}{8}$

$\frac{1}{4}$

$\frac{13}{16}$

Explanation

$\frac{7}{8}-\frac{3}{16}$

In order to solve this problem, we first have to find common denominators.

$\frac{7}{8}\times\frac{2}{2}=\frac{14}{16}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{14}{16}-\frac{3}{16}=\frac{11}{16}$

Solve:

$\frac{7}{8}-\frac{3}{16}$

$\frac{11}{16}$

$\frac{4}{16}$

$\frac{4}{8}$

$\frac{1}{4}$

$\frac{13}{16}$

Explanation

$\frac{7}{8}-\frac{3}{16}$

In order to solve this problem, we first have to find common denominators.

$\frac{7}{8}\times\frac{2}{2}=\frac{14}{16}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{14}{16}-\frac{3}{16}=\frac{11}{16}$

$\frac{3}{4}+\frac{1}{3}=$

$1\frac{1}{12}$

$\frac{12}{13}$

$\frac{4}{7}$

$\frac{7}{4}$

$\frac{13}{24}$

Explanation

$\frac{3}{4}+\frac{1}{3}$

In order to solve this problem, we first have to find common denominators.

$\frac{3}{4}\times\frac{3}{3}=\frac{9}{12}$

$\frac{1}{3}\times\frac{4}{4}=\frac{4}{12}$

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{9}{12}+\frac{4}{12}=\frac{13}{12}$

$\frac{13}{12}=1\frac{1}{12}$ because can go into one time, with one left over.

$\frac{3}{4}+\frac{1}{3}=$

$1\frac{1}{12}$

$\frac{12}{13}$

$\frac{4}{7}$

$\frac{7}{4}$

$\frac{13}{24}$

Explanation

$\frac{3}{4}+\frac{1}{3}$

In order to solve this problem, we first have to find common denominators.

$\frac{3}{4}\times\frac{3}{3}=\frac{9}{12}$

$\frac{1}{3}\times\frac{4}{4}=\frac{4}{12}$

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{9}{12}+\frac{4}{12}=\frac{13}{12}$

$\frac{13}{12}=1\frac{1}{12}$ because can go into one time, with one left over.

Solve the following:

$\frac{2}{3}-\frac{1}{8}$

$\frac{13}{24}$

$\frac{1}{5}$

$\frac{12}{24}$

$\frac{1}2{}$

$\frac{3}7{}$

Explanation

$\frac{2}{3}-\frac{1}{8}$

In order to solve this problem, we first have to find common denominators.

$\frac{2}{3}\times\frac{8}{8}=\frac{16}{24}$

$\frac{1}{8}\times\frac{3}{3}=\frac{3}{24}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{16}{24}-\frac{3}{24}=\frac{13}{24}$

Solve the following:

$\frac{2}{3}-\frac{1}{8}$

$\frac{13}{24}$

$\frac{1}{5}$

$\frac{12}{24}$

$\frac{1}2{}$

$\frac{3}7{}$

Explanation

$\frac{2}{3}-\frac{1}{8}$

In order to solve this problem, we first have to find common denominators.

$\frac{2}{3}\times\frac{8}{8}=\frac{16}{24}$

$\frac{1}{8}\times\frac{3}{3}=\frac{3}{24}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{16}{24}-\frac{3}{24}=\frac{13}{24}$

$\frac{1}{4}-\frac{1}{7}$

$\frac{0}{3}$

$\frac{3}{28}$

$-\frac{0}{3}$

$\frac{1}{12}$

Explanation

$\frac{1}{4}-\frac{1}{7}$

In order to solve this problem, we first have to find common denominators.

$\frac{1}{4}\times\frac{7}{7}=\frac{7}{28}$

$\frac{1}{7}\times \frac{4}{4}=\frac{4}{28}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{7}{28}-\frac{4}{28}=\frac{3}{28}$

$\frac{1}{4}+\frac{1}{2}$

$\frac{3}{4}$

$\frac{2}{6}$

$\frac{1}{3}$

$\frac{2}{4}$

$\frac{1}{2}$

Explanation

$\frac{1}{4}+\frac{1}{2}$

In order to solve this problem, we first have to find common denominators.

$\frac{1}{2}\times\frac{2}{2}=\frac{2}{4}$

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{1}{4}+\frac{2}{4}=\frac{3}{4}$

$\frac{3}{4}-\frac{2}{3}$

$\frac{1}{12}$

$\frac{1}{1}$

$\frac{1}{0}$

$\frac{1}{24}$

$\frac{1}{2}$

Explanation

$\frac{3}{4}-\frac{2}{3}$

In order to solve this problem, we first have to find common denominators.

$\frac{3}{4}\times\frac{3}{3}=\frac{9}{12}$

$\frac{2}{3\time}\times\frac{4}{4}=\frac{8}{12}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{9}{12}-\frac{8}{12}=\frac{1}{12}$